Academia Lab #relative-velocity 0 / 24 solved

Physics Lab · Iterative

Relative velocity: directions, angles, rivers and rain

Sit inside one vehicle and watch everything else — that's relative velocity. Every topic here runs the same loop: read the idea → see it move → solve problems → check yourself. Nothing is locked; jump to any stage, and the page remembers where you were.

20.1–20.2 Same & opposite direction20.3 At an angle21 River–boat22 Rain24 problems6 self-checks
Stage 1 · Read

The idea

The rule VXY = VX − VY and the four-step method.

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Stage 2 · See

Watch it move

Four sims: seat view, angles, river crossings, rain and umbrellas.

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Stage 3 · Solve

24 problems

Six levels, each solution revealed one step at a time.

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Stage 4 · Check

Self-check

Six quick questions with instant feedback and explanations.

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Change your seat

Car A starts at +10 m/s and car B at −20 m/s. The sign post C stands still. Pick where you sit and watch how the same road looks different.

Positive means to the right, negative means to the left. The yellow outline marks the vehicle you are sitting in. Notice that the road itself and the sign C also seem to move when you sit in a moving car.

The rule — 20.1 same direction · 20.2 opposite direction

To find the velocity of X relative to Y, subtract the velocity of Y, because you are removing your own motion from what you see.

VXY = VX − VY Read it as: the velocity of X as seen from Y.

Opposite directions

Give one of them a minus sign. Subtracting a negative number adds, so the relative speed is the sum of the two speeds: 10 + 20 = 30 m/s.

Same direction

Both have the same sign, so the relative speed is the difference of the two speeds: 30 − 20 = 10 m/s.

Swap the viewer

The answer keeps its size and flips its sign: VAB = −VBA.

Here is the example from your notes: A = +10 m/s, B = −20 m/s, C stationary. Each cell is the velocity of the row object as seen from the column object.

ObjectSeen from ASeen from BSeen from C (ground)
A0+30 m/s+10 m/s
B−30 m/s0−20 m/s
C−10 m/s+20 m/s0

Look at the middle column of the top row: VAB = 10 − (−20) = +30 m/s. That is the same +30 you saw when you sat in B.

The four-step method

  1. Choose the positive direction. Usually the direction of the first object.
  2. Write every velocity with its sign. Anything moving the other way gets a minus.
  3. Subtract the viewer. For X relative to Y, calculate VX − VY.
  4. Read the answer. The sign tells the direction, the size tells the speed. Check the units.

Mistakes to avoid:

20.3 — At an angle (the general case)

When two velocities are neither parallel nor opposite, "add a minus sign" is not enough. Here is the trick: draw both velocities as arrows starting from the same point, to the same scale. The arrow that joins their two tips — pointing toward the object you want the velocity of — is the relative velocity. No reversing, no reassembling: just join the tips.

R = √(v1² + v2² − 2v1v2cos β) β is the angle between the two arrows as drawn from the same point. This is the ordinary law of cosines applied to the triangle they form.

You may also see this written as R = √(v1² + v2² + 2v1v2cos α), where α is the angle after reversing the viewer's vector first. Both give the same number: α is simply the supplement of β (α = 180° − β), and cos(180° − β) = −cos β, so the two formulas are the same formula written two ways. Use whichever picture is easier to draw.

Blue: A. Orange: B. Green: the relative velocity you asked for, drawn tip-to-tip. Try β = 0° and β = 180° — you should get back the same-direction and opposite-direction rules from above.

21. River–boat problems

A boat with still-water speed Vb crosses a river of width d that flows at Vt. Whatever angle the boat is steered at, its actual path over the ground is the vector sum of these two velocities. There are three classic ways to steer, and they trade off against each other.

Type 1 — shortest distance

Steer upstream so the current is exactly cancelled: zero drift, but the longest crossing time. Needs Vb > Vt.

Type 2 — shortest time

Steer straight across (90° to the bank). This is the fastest crossing, t = d / Vb, but the current still carries you downstream.

Type 3 — with the flow

Steer downstream on purpose. Both drift and time increase — useful only when a specific downstream point is the real target.

Let θ be the angle the boat's heading makes with the straight-across direction: positive θ means aimed upstream, negative θ means aimed downstream.

Vacross = Vbcos θ    Valong bank = Vt − Vbsin θ Time to cross: t = d / Vacross. Drift: Valong bank × t (positive = downstream, negative = upstream).

Positive θ = aimed upstream (fights the current). Negative θ = aimed downstream ("with the flow"). The diagram is schematic, not drawn exactly to scale for extreme values.

22. Rain problems

Find the velocity of the rain relative to the observer — that is the direction the rain seems to come from, and it is exactly the direction an umbrella should be tilted along. Rain always falls straight down relative to the ground; wind and walking only change what it looks like to the person underneath it.

Type 1

Rain falls, pedestrian moves, no wind. Just subtract the pedestrian's velocity from the rain's.

Type 2

Rain falls, wind blows, pedestrian stands still. The wind alone tilts the rain.

Type 3

Wind and pedestrian move the same way. Combine wind with rain first, then subtract the pedestrian.

Type 4

Wind blows against the pedestrian. Same two steps, opposite sign on the wind.

Type 5

An inclined road, or extra axes. Same method — resolve everything onto a common set of axes first.

Rx = (wind, if any) − Vpedestrian    Ry = Vrain (straight down) R = √(Rx² + Ry²). The umbrella tilts by tan−1(|Rx| / Ry) from the vertical, toward the direction Rx points.

Blue streaks: the rain's velocity relative to you. Orange: the umbrella, held along the streaks. Turn on a wind to see Types 2–4.

Check yourself #check-yourself

Stage 4 of the loop. Six quick questions across the whole topic — answer in any order, retry a wrong one straight away, and read the reason every time.

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